Question

4
What is the probability of getting o when
a number is chosen from the numbers
0, 1, 2, 3, 4, 5, 6, 7, 8, 9?​

Answer 1

Answer:

14.3%

Step-by-step explanation:

Replacement does indeed mean that the same one cannot be used twice.

Order is not important, so we are using combinations in this case. Out of $_{8}$$C_{2}$=28 possible sums, only 4 (7 + 0, 6 + 1, 5 + 2, 4 + 3) will yield 7. The probability is then $\frac{4}{28}$×100%=14.3%.

Answer 2

Answer:

1/10 or 0.1

Step-by-step explanation:

All outcomes = 0, 1, 2, 3, 4, 5, 6, 7, 8, 9

possible number of outcomes of getting 0 = 1

total no. of outcomes = 10

probability = possible number of outcomes / total no. of outcomes

probability = 1/10 or 0.1

please mark brainliest if it helped you