Question

4. What is the Sum of zeros of the Polynomial 8x^2+32x+24

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Answer 1

Answer:

8x²+32x+24.

x²+4x+3 3x²=1×3

. . 3×1

x²+1x+3x+3=0

x(x+1)+3(x+1)=0

(x+1)+(x+3)=0

x+1=0;x+3=0

x=-1;x=-3//

Answer 2

Given:
A polynomial=8x^2+32x+24

To find:

The sum of the zeroes

Solution:

The polynomial's zeroes' sum is -4.

We can obtain the required sum by taking the coefficients of $x^{2}$ and x from the given polynomial.

Here, the given polynomial is-

8x^2+32x+24

The sum's value= -b/a, where b is x's coefficient and a is the coefficient of $x^{2}$.

So, a=8, b=32.

Using the values, we get

= -32/8

= -4

Therefore, the polynomial's zeroes' sum is -4.