Question

4) What is the volume of 10 M acetic acid required to prepare 400 mL of 1 M solution?

Can any plz solve n post the solution

Answer 1

$\large \rm {\underbrace{\underline{⍗Elucidation:-}}}$

➻According to dilution law,

$\qquad \qquad \cal \to \purple {\boxed{\boxed{M_{1}V_{1} =M_{2}V_{2}}}}$

$\qquad \qquad \sf \bullet {M_{1} =10M}$

$\qquad \qquad \sf \bullet {V_{1} =?}$

$\qquad \qquad \sf \bullet {M_{2} =1M}$

$\qquad \qquad \sf \bullet {V_{2} =400mL}$

➻Applying the formula,

$\qquad \qquad \sf \to {M_{1}V_{1} =M_{2}V_{2}}$

$\qquad \qquad \sf \mapsto {10×V_{1} =1×400}$

$\large \qquad \qquad \sf \mapsto {V_{1} =\frac{1×400}{10}}$

$\large \qquad \qquad \sf \mapsto {V_{1} =\frac{400}{10}}$

$\large \qquad \qquad \sf \mapsto {V_{1} =\frac{40{\cancel{0}}}{\cancel{10}}}$

$\qquad \qquad \cal \mapsto \pink {\boxed{\boxed{V_{1}=40mL}}}$

➻[OR],

$\qquad \qquad \cal \mapsto \orange {\boxed{\boxed{V_{1}=0.04Litres}}}$

➻The volume of 10 M acetic acid required to prepare 400mL of 1 M solution is 40mL respectively.

Answer 2

Answer:40

Step-by-step explanation:

given

V1 = ?

N1 = 10

V2 = 400

N2 = 1

formula : V1N1 = V2N2

V1 × 10 = 400× 1

V1 = 400 ÷ 1

V1 = 40

may be this would be helpful for