Math, asked by Anonymous, 3 months ago



4.What must be the length of a 5m diameter aluminum wire so that it can be twisted through one complete revolution without exceeding a shearing stress of 42 MN/M2.Take G=27GN/M2 CO3

Answers

Answered by vikashpatnaik2009
3

Answer:

three

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Answered by vishalbawankar742
1

Step-by-step explanation:

What must be the length of a 5mm dia aluminium wire so that it can be twisted through 1 complete revolution without exceeding a shear of 42N/mm2. Take, G=27 GPa

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