Question

4. What temperature must a solution of 50 g of KCI in 100 g of water be raised to for all of the KCl to dissolve?​

Answer 1

Answer:

100 g

Explanation:

The problem provides you with the solubility of potassium chloride,  

KCl

, in water at  

20

∘

C

, which is said to be equal to  

34 g / 100 g H

2

O

.

This means that at  

20

∘

C

, a saturated solution of potassium chloride will contain  

34 g

of dissolved salt for every  

100 g

of water.

As you know, a saturated solution is a solution that holds the maximum amount of dissolved salt. Adding more solid to a saturated solution will cause the solid to remain undissolved.

In your case, you can create a saturated solution of potassium chloride by dissolving  

34 g

of salt in  

100 g

of water at  

20

∘

C

.

Now, your goal here is to figure out how much potassium chloride can be dissolved in  

300 g

of water at this temperature. To do that, use the given solubility as a conversion factor to take you from grams of salt to grams of water

300

g H

2

O

⋅

34 g KCl

100

g H

2

O

=

102 g KCl

Explanation: