4. What volume of 0.1 N oxalic acid solution can be reduced
by 250 g of an 8 per cent by weight KMnO solution?
a. 6.3 litre b. 12.6 litre c. 25.2 litre d. 0.63 litre
4
Answers
Answered by
3
Explanation:
factor for H
2
C
2
O
4
=2
Equivalent weight =
2
M
Normality =
equivalentweight×volume(inmL)
weight×1000
0.1=
(
2
126
)×250
weight×1000
Therefore, weight = 1.575g
answer is 1.575g
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