Question

4. What volume of 0.1 N oxalic acid solution can be reduced
by 250 g of an 8 per cent by weight KMnO solution?
a. 6.3 litre b. 12.6 litre c. 25.2 litre d. 0.63 litre
4​

Answer 1

Explanation:

factor for H

2

C

2

O

4

=2

Equivalent weight =

2

M

Normality =

equivalentweight×volume(inmL)

weight×1000

0.1=

(

2

126

)×250

weight×1000

Therefore, weight = 1.575g

answer is 1.575g