Question

4. What would be the yearly interest on Rs5000 at 10 p.c.p.a.?



ans.​

Answer 1

Answer:

1

st

year

Principal, P=Rs.5000

Time, T=1 year

Rate of interest ,R=6%

∴simple Interest, SI=

100

PTR

=

100

5000×10×6

=Rs.300

∴Amount=P+SI=Rs.5300

2nd year

Principal = Amount of 1st year=Rs.5300

Rate of interest =8%

Time =1 year

∴ Interest =

100

5300×1×8

=Rs.424

∴ Amount =Rs.(5300+424)=Rs.5724

The interest of 2nd year is the required compound interest. So, C.I=rs.424 and the required amount is Rs.5724

Answer 2

Answer:

Given :

Principal (P)= ₹5000

Rate (R) = 10%

Time (T) = 1 year

Step-by-step explanation:

Now , Interest =

$\frac{p \times r\times\:t }{100} </strong></p><p><strong>[tex] \frac{p \times r\times\:t }{100}$

$= \frac{5000 \times 10 \times 1}{100} = \frac{50000}{100} = 500rupees$