Question

4. Which of the following equation has roots 2 and 5
2-78-10 = 0
cese 2+72 +10=0
be X2-77 +10 = 0
de x2+7-10 = 0
.​

Answer 1

$GIVEN :-</p><p></p><p>A ᴀʟᴏɴᴇ ᴄᴀɴ ᴅᴏ ᴀ ᴡᴏʀᴋ ɪɴ 4 ᴅᴀʏs .</p><p></p><p>B ᴀʟᴏɴᴇ ᴄᴀɴ ᴅᴏ ᴀ ᴡᴏʀᴋ ɪɴ 6 ᴅᴀʏs .</p><p></p><p>TO FIND :-</p><p></p><p>Tʜᴇ ᴛɪᴍᴇ ᴛʜᴇʏ ᴡᴏᴜʟᴅ ᴛᴀᴋᴇ ɪғ ᴛʜᴇʏ ᴡᴏʀᴋ ᴛᴏɢᴇᴛʜᴇʀ .</p><p></p><p>SOLUTION :-</p><p></p><p>ʟᴇᴛ,</p><p></p><p>Tʜᴇ ᴛᴏᴛᴀʟ ᴡᴏʀᴋ = 1</p><p></p><p>Fᴏʀ 'A' :-</p><p></p><p>➪ A ᴄᴀɴ ᴀʟᴏɴᴇ ᴅᴏ ᴛʜᴇ 1 ᴡᴏʀᴋ ɪɴ 4 ᴅᴀʏs .</p><p></p><p>☯︎ Sᴏ, ɪɴ ᴏɴᴇ ᴅᴀʏ A ᴄᴀɴ ᴅᴏ = \bf\red{\dfrac{1}{4}}41 ᴡᴏʀᴋ .</p><p></p><p>Fᴏʀ 'B' :-</p><p></p><p>➪ B ᴄᴀɴ ᴀʟᴏɴᴇ ᴅᴏ ᴛʜᴇ 1 ᴡᴏʀᴋ ɪɴ 6 ᴅᴀʏs .</p><p></p><p>☯︎ Sᴏ, ɪɴ ᴏɴᴇ ᴅᴀʏ B ᴄᴀɴ ᴅᴏ = \bf\red{\dfrac{1}{6}}61 ᴡᴏʀᴋ .</p><p></p><p>Fᴏʀ ʙᴏᴛʜ 'A' ᴀɴᴅ 'B' :-</p><p></p><p>➪ ʟᴇᴛ, A ᴀɴᴅ B ᴛᴏɢᴇᴛʜᴇʀ ᴅᴏ ᴛʜᴇ 1 ᴡᴏʀᴋ ɪɴ X ᴅᴀʏs .</p><p></p><p>☯︎ Sᴏ, ɪɴ ᴏɴᴇ ᴅᴀʏ A ᴀɴᴅ B ᴄᴀɴ ᴅᴏ = \bf\red{\dfrac{1}{X}}X1 ᴡᴏʀᴋ .</p><p></p><p>\bf{:\implies\:\dfrac{1}{4}\:+\:\dfrac{1}{6}\:=\:\dfrac{1}{X}\:}:⟹41+61=X1</p><p></p><p>\rm{:\implies\:\dfrac{3\:+\:2}{12}\:=\:\dfrac{1}{X}\:}:⟹123+2=X1</p><p></p><p>\rm{:\implies\:\dfrac{5}{12}\:=\:\dfrac{1}{X}\:}:⟹125=X1</p><p></p><p>\bf\green{:\implies\:X\:=\:\dfrac{12}{5}\:}:⟹X=512</p><p></p><p>➳ X = 12/5 = 2.4 Days .</p><p></p><p>\huge\red\therefore∴ Tʜᴇ ᴛɪᴍᴇ ᴛʜᴀᴛ ʙᴏᴛʜ A ᴀɴᴅ B ᴡᴏᴜʟᴅ ᴛᴀᴋᴇ ɪғ ᴛʜᴇʏ ᴡᴏʀᴋ ᴛᴏɢᴇᴛʜᴇʀ ɪs "2.4 ᴅᴀʏs" .</p><p></p><p>$

Answer 2

$GIVEN :- A ᴀʟᴏɴᴇ ᴄᴀɴ ᴅᴏ ᴀ ᴡᴏʀᴋ ɪɴ 4 ᴅᴀʏs . B ᴀʟᴏɴᴇ ᴄᴀɴ ᴅᴏ ᴀ ᴡᴏʀᴋ ɪɴ 6 ᴅᴀʏs . TO FIND :- Tʜᴇ ᴛɪᴍᴇ ᴛʜᴇʏ ᴡᴏᴜʟᴅ ᴛᴀᴋᴇ ɪғ ᴛʜᴇʏ ᴡᴏʀᴋ ᴛᴏɢᴇᴛʜᴇʀ . SOLUTION :- ʟᴇᴛ, Tʜᴇ ᴛᴏᴛᴀʟ ᴡᴏʀᴋ = 1 Fᴏʀ 'A' :- ➪ A ᴄᴀɴ ᴀʟᴏɴᴇ ᴅᴏ ᴛʜᴇ 1 ᴡᴏʀᴋ ɪɴ 4 ᴅᴀʏs . ☯︎ Sᴏ, ɪɴ ᴏɴᴇ ᴅᴀʏ A ᴄᴀɴ ᴅᴏ = \bf\red{\dfrac{1}{4}}41 ᴡᴏʀᴋ . Fᴏʀ 'B' :- ➪ B ᴄᴀɴ ᴀʟᴏɴᴇ ᴅᴏ ᴛʜᴇ 1 ᴡᴏʀᴋ ɪɴ 6 ᴅᴀʏs . ☯︎ Sᴏ, ɪɴ ᴏɴᴇ ᴅᴀʏ B ᴄᴀɴ ᴅᴏ = \bf\red{\dfrac{1}{6}}61 ᴡᴏʀᴋ . Fᴏʀ ʙᴏᴛʜ 'A' ᴀɴᴅ 'B' :- ➪ ʟᴇᴛ, A ᴀɴᴅ B ᴛᴏɢᴇᴛʜᴇʀ ᴅᴏ ᴛʜᴇ 1 ᴡᴏʀᴋ ɪɴ X ᴅᴀʏs . ☯︎ Sᴏ, ɪɴ ᴏɴᴇ ᴅᴀʏ A ᴀɴᴅ B ᴄᴀɴ ᴅᴏ = \bf\red{\dfrac{1}{X}}X1 ᴡᴏʀᴋ . \bf{:\implies\:\dfrac{1}{4}\:+\:\dfrac{1}{6}\:=\:\dfrac{1}{X}\:}:⟹41+61=X1 \rm{:\implies\:\dfrac{3\:+\:2}{12}\:=\:\dfrac{1}{X}\:}:⟹123+2=X1 \rm{:\implies\:\dfrac{5}{12}\:=\:\dfrac{1}{X}\:}:⟹125=X1 \bf\green{:\implies\:X\:=\:\dfrac{12}{5}\:}:⟹X=512 ➳ X = 12/5 = 2.4 Days . \huge\red\therefore∴ Tʜᴇ ᴛɪᴍᴇ ᴛʜᴀᴛ ʙᴏᴛʜ A ᴀɴᴅ B ᴡᴏᴜʟᴅ ᴛᴀᴋᴇ ɪғ ᴛʜᴇʏ ᴡᴏʀᴋ ᴛᴏɢᴇᴛʜᴇʀ ɪs "2.4 ᴅᴀʏs" .GIVEN:−A ᴀʟᴏɴᴇᴄᴀɴᴅᴏᴀᴡᴏʀᴋɪɴ 4 ᴅᴀʏs.B ᴀʟᴏɴᴇᴄᴀɴᴅᴏᴀᴡᴏʀᴋɪɴ 6 ᴅᴀʏs.TOFIND:−Tʜᴇᴛɪᴍᴇᴛʜᴇʏᴡᴏᴜʟᴅᴛᴀᴋᴇɪғᴛʜᴇʏᴡᴏʀᴋᴛᴏɢᴇᴛʜᴇʀ.SOLUTION:−ʟᴇᴛ,Tʜᴇᴛᴏᴛᴀʟᴡᴏʀᴋ=1Fᴏʀ ′A′ :−➪ A ᴄᴀɴᴀʟᴏɴᴇᴅᴏᴛʜᴇ1ᴡᴏʀᴋɪɴ4ᴅᴀʏs.☯︎Sᴏ,ɪɴᴏɴᴇᴅᴀʏAᴄᴀɴᴅᴏ= 4141 ᴡᴏʀᴋ.Fᴏʀ ′B′ :−➪ B ᴄᴀɴᴀʟᴏɴᴇᴅᴏᴛʜᴇ1ᴡᴏʀᴋɪɴ6ᴅᴀʏs.☯︎Sᴏ,ɪɴᴏɴᴇᴅᴀʏBᴄᴀɴᴅᴏ= 6161 ᴡᴏʀᴋ.Fᴏʀ ʙᴏᴛʜ ′A′ ᴀɴᴅ ′B′ :−➪ʟᴇᴛ, A ᴀɴᴅ B ᴛᴏɢᴇᴛʜᴇʀᴅᴏᴛʜᴇ1ᴡᴏʀᴋɪɴXᴅᴀʏs.☯︎Sᴏ,ɪɴᴏɴᴇᴅᴀʏ A ᴀɴᴅ B ᴄᴀɴᴅᴏ= X1X1 ᴡᴏʀᴋ.:⟹41+61=X1:⟹41+61=X1:⟹123+2=X1:⟹123+2=X1:⟹125=X1:⟹125=X1:⟹X=512:⟹X=512➳ X =12/5= 2.4 Days .∴∴ Tʜᴇᴛɪᴍᴇᴛʜᴀᴛʙᴏᴛʜ A ᴀɴᴅ B ᴡᴏᴜʟᴅᴛᴀᴋᴇɪғᴛʜᴇʏᴡᴏʀᴋᴛᴏɢᴇᴛʜᴇʀɪs"2.4 ᴅᴀʏs".$