Question

4. Which term of the AP: 18, 23, 28, 33, ... is 98?
(a) 15th
(6) 16th
c) 17th
(d) 18th​

Answer 1

Answer:

an=98

a+n-1*d

18+(n-1)*5=98

n-1=(98-18)/5

n-1=80/5=16

n=17

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Answer 2

Answer:

98 is$17^{th}$ term of the given AP series.

Given:

Which term of the AP: 18, 23, 28, 33, ... is 98

Solution:

in the given series,

a = 18, which is the first term.

d = 23 – 18 = 5 , which is the difference between the two terms.

By using the formula,

$t_{n}$ = a + (n-1) d

$t_{n}$ = 98

98 = 18 + (n-1) 5

98 – 18 = 5n – 5

80 + 5 = 5n

85 = 5n

n = 17

Result:

98 is$17^{th}$ term of the given AP series.