Question

4 women & 6 men have to be seated in a row given that no two women can sit together. how many different arrangements are there

Answer 1

Arranging the 6 men in 6 factorial ways we are left with 7 spaces, out of which 4 spaces are to be selected in 7C4 ways.

In these spaces 4 women are going to sit in 4 factorial ways.

So the total number of different arrangements are 6! * 4! * 7C4 = 604800 ways