Question

4. Write a Pythagorean triplet whose one member is the following. a. 14
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Answer 1

Answer:

14, 48 and 50

Step-by-step explanation:

Let us assume 2 m=14 therefore m=7

Now $m^{2}$  + 1 = $7^{2}$  + 1 = 49 + 1 = 50

And $m^{2}$  − 1 = $7^{2}$  − 1 = 49 − 1 = 48

Test : $14^{2}$  + $48^{2}$  = 196 + 1304 = 2500 = $50^{2}$

 

Hence the triplet is 14,48 and 50 Answer

Answer 2

${x}^{2} + {y}^{2} = {z}^{2}$