Question

4.Write the Zeroes of
P(x) = x2-3x +2.​

Answer 1

Answer:

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Answer 2

Answer:

$\huge\bold\green{Given :-}$

The Zeroes of P(x) = x² - 3x + 2

$\huge\bold\red{Solution :-}$

➪ x² - 3x + 2 = 0

➭ x² - (2 + 1)x + 2 = 0

➭ x² - 2x - x + 2 = 0

➭ x(x - 2) - 1(x - 2) = 0

➭ (x - 2) (x - 1) = 0

➭ (x - 2) = 0

➭ x - 2 = 0

➭ x = 2

Either,

➭ (x - 1) = 0

➭ x - 1 = 0

➭ x = 1

∴ The answer of this question is

x = 1, 2