Math, asked by pkumar516, 3 days ago

4^(x^2+2)-0.2^(x^2+2)+8=0​

Answers

Answered by sandeep5610001
2

Answer:

Step-by-step explanation:

4^(x2+2)-0.2(x2+2)+8=0

We add all the numbers together, and all the variables

4^(+x^2+2)-0.2(+x^2+2)+8=0

We multiply parentheses

4^(+x^2+2)-0.2x^2-0.4+8=0

We add all the numbers together, and all the variables

-0.2x^2+4^(+x^2+2)+7.6=0

We move all terms containing x to the left, all other terms to the right

-0.2x^2+4^(+x^2+2)=-7.6

Answered by deadboi003
1

Answer:

4^(x2+2)-0.2(x2+2)+8=0

We add all the numbers together, and all the variables

4^(+x^2+2)-0.2(+x^2+2)+8=0

We multiply parentheses

4^(+x^2+2)-0.2x^2-0.4+8=0

We add all the numbers together, and all the variables

-0.2x^2+4^(+x^2+2)+7.6=0

We move all terms containing x to the left, all other terms to the right

-0.2x^2+4^(+x^2+2)=-7.6

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