Question

4^(x-2)-2^(x+1)=0
Find x​

Answer 1

Answer:

2^2×(x-2)-2^(x+1)=0

2x-4-x+1=0

x-3=0

x=3

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Answer 2

hey buddy your answer is here

$\ {4}^{x - 2} { - 2}^{x + 1 = 0 } \\ {2}^{2x - 4} = {2}^{x + 1} \\ hence \: bases \: are \: same \: then \: power \: must \: be \: equal \\ 2x - 4= x + 1 \\ 2x - x = 1 + 4 \\ x = 5$

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