Question

(4 -x)^2 - 2x

factorise​

Answer 1

Answer:

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Answer 2

Answer:

Answer is :-

${(4 - x)}^{2} - 2x \\ > (16 + {x}^{2} - 8x) - 2x \\ > {x}^{2} - 8x - 2x + 16 \\ > x(x - 8) - 2(x - 8) \\ > (x - 8)(x - 2)$