Question

(4 -x)^2 - 2x

factorise​

Answer 1

$\huge \underline \mathbb \purple {ANSWER}$

${(4 - x)}^{2} - 2x = 0 \\ \\ {(4)}^{2} - 2 \times x \times 4 + {x}^{2} - 2x = 0 \\ \\ 16 - 8x + {x}^{2} - 2x = 0 \\ \\ {x}^{2} - 8x - 2x + 16 = 0 \\ \\ {x}^{2} - 10x + 16 = 0 \\ \\ {x}^{2} - 8x - 2x + 16 = 0 \\ \\ x(x - 8) - 2(x - 8) = 0 \\ \\ (x - 2)(x - 8) = 0 \\ \\ x = 2 \\ \\ x = 8$