Math, asked by pallavishende87134, 1 month ago

4/x^2+5x+6 -3/x+3 =1/2

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Answers

Answered by Gayatrishende1234
17

 \\   \frac{4}{ {x}^{2} + 5x + 6 }  -  \frac{3}{x + 3}  =  \frac{1}{2}

 \\  =  >  \frac{4}{ {x}^{2}  + 2x + 3x + 6} -  \frac{3}{ x + 3}   =  \frac{1}{2}

 \\  =  >  \frac{4}{x(x + 2) +3(x + 2)}  -  \frac{3}{x +  3}  =  \frac{1}{2}

 \\  =  >  \frac{4}{(x + 2)(x + 3)}  -  \frac{3}{x + 3}  =  \frac{1}{2}

 \\  =  >  \frac{4 - 3(x + 2)}{(x + 2)(x + 3)}  =  \frac{1}{2}

 \\  =  > \frac{4 - 3x - 6}{ {x}^{2} + 5x + 6 }   =  \frac{1}{2}

 \\  =  >  \frac{ - 3x - 2}{ {x}^{2} + 5x + 6 }  =  \frac{1}{2}

 \\  =  >  {x}^{2}  + 5x + 6 =  - 6x - 4

 \\  =  >  {x}^{2}  + 5x + 6 + 6x + 4 = 0

  \\ =  >  {x}^{2}  + 11x + 10 = 0

 \\  =  >  {x }^{2}  + x + 10x +10 = 0

 \\  =  > x(x + 1) + 10(x + 1) = 0

 \\  =  > (x + 1) \: (x + 10) = 0

 \\  =  > x + 1 = 0 \:  \:  \: or, \:  \: x + 10 = 0

 \\ :-  \:  \:  x =  - 1 \:  \:  \: :- \:  \: x =  - 10

 \\ The \: value \: of \: x \:  =  - 1 \: \:  or \:  - 10

I hope this will help you dear..

Always stay safe and stay healthy..

Answered by XxTheBrainlyLegendxX
6

Answer:

 \\   \frac{4}{ {x}^{2} + 5x + 6 }  -  \frac{3}{x + 3}  =  \frac{1}{2}

 \\  =  >  \frac{4}{ {x}^{2}  + 2x + 3x + 6} -  \frac{3}{ x + 3}   =  \frac{1}{2}

 \\  =  >  \frac{4}{x(x + 2) +3(x + 2)}  -  \frac{3}{x +  3}  =  \frac{1}{2}

 \\  =  >  \frac{4}{(x + 2)(x + 3)}  -  \frac{3}{x + 3}  =  \frac{1}{2}

 \\  =  >  \frac{4 - 3(x + 2)}{(x + 2)(x + 3)}  =  \frac{1}{2}

 \\  =  > \frac{4 - 3x - 6}{ {x}^{2} + 5x + 6 }   =  \frac{1}{2}

 \\  =  >  \frac{ - 3x - 2}{ {x}^{2} + 5x + 6 }  =  \frac{1}{2}

 \\  =  >  {x}^{2}  + 5x + 6 =  - 6x - 4

 \\  =  >  {x}^{2}  + 5x + 6 + 6x + 4 = 0

  \\ =  >  {x}^{2}  + 11x + 10 = 0

 \\  =  >  {x }^{2}  + x + 10x +10 = 0

 \\  =  > x(x + 1) + 10(x + 1) = 0

 \\  =  > (x + 1) \: (x + 10) = 0

 \\  =  > x + 1 = 0 \:  \:  \: or, \:  \: x + 10 = 0

 \\ :-  \:  \:  x =  - 1 \:  \:  \: :- \:  \: x =  - 10

 \\ The \: value \: of \: x \:  =  - 1 \: \:  or \:  - 10

I hope this will help you dear..

Always stay safe and stay healthy..

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