Question

4/ (x+2) (x-5)- 1/ (x+2)(x+3)

Answer 1

Question:

Solve:-

$\dfrac{4}{(x+2)}(x-5)$$-\dfrac{1}{(x+2)}(x+3)$

Solution:

Answer:

$\dfrac{3x-23}{x+2}$

Step-by-step explanation:

$\dfrac{4}{(x+2)}(x-5)$$-\dfrac{1}{(x+2)}(x+3)$

$\to\dfrac{4x-20}{x+2}$$-\dfrac{x+3}{x+2}$

$\to\dfrac{(4x-20)-(x+3)}{x+2}$

$\to\dfrac{4x-20-x-3}{x+2}$

$\to\dfrac{4x-x-20-3}{x+2}$

$\to\dfrac{3x-23}{x+2}$

$\therefore \dfrac{4}{(x+2)}(x-5)$$-\dfrac{1}{(x+2)}(x+3)$

$=\dfrac{3x-23}{x+2}$