Question

(⅔)^-4 x (27/8)^-2 plz answer fast showing steps

Answer 1

Answer:

$\frac{5}{4}$

Step-by-step explanation:

( 27/8 )^2/3 - ( 1/4 )^-2 + 5^0

= ( 3³/2³ )^2/3 - ( 1/2² )^-2 + 1

[ Since a^0 = 1 ]

= [ ( 3/2 )³ ]^2/3- [ ( 1/2 )² ]^-2 + 1

= ( 3/2 )^3×2/3 - ( 1/2 )^-2/2 + 1

= ( 3/2 )² - ( 1/2 )^-1 + 1

= 9/4 - ( 2/1 ) + 1

= 9/4 - 2 + 1

= 9/4 - 1

= ( 9 - 4 )/4

= 5/4

$\left[\begin{array}{ccc}HOPE\\IT\\HELPS\end{array}\right] \left \{ {{AAKRIT I05} \atop {SAY THNX}} \right. \neq \int\limits Or ElseCanReportIt$

Answer 2

Answer:

27/8 )^2/3 - ( 1/4 )^-2 + 5^0

= ( 3³/2³ )^2/3 - ( 1/2² )^-2 + 1

[ Since a^0 = 1 ]

= [ ( 3/2 )³ ]^2/3- [ ( 1/2 )² ]^-2 + 1

= ( 3/2 )^3×2/3 - ( 1/2 )^-2/2 + 1

= ( 3/2 )² - ( 1/2 )^-1 + 1

= 9/4 - ( 2/1 ) + 1

= 9/4 - 2 + 1

= 9/4 - 1

= ( 9 - 4 )/4

= 5/4

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