Question

4 - x - 2x² = 0
please solve it​

Answer 1

Step-by-step explanation:

$- 2 {x}^{2} - x + 4 \\ 2 {x}^{2} + x - 4 \\ \\ \frac{ - b + \: or \: - \sqrt{ {b}^{2} - 4ac } }{2a} \\ just \: putting \: values... \\ \frac{ - 1 + \: or \: - \sqrt{1 - ( - 8)} }{2(2)} \\ \frac{ - 1 + 3}{4} \: \: \: \: \: \: \: \: \: or \: \: \: \frac{ - 1 - 3}{4} \\ \\ 2 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: or \: \: \: \: \: - 1$

Answer 2

Answer:

(-1+√33)/4 and(-1-√33)/4

Step-by-step explanation: we can solve this by sridharacharya formula -b±√(b²-4ac)/2a

first 4-x-2x²=0  → 2x²+x-4=0

x=-1±√[1²-4(2)(-4)]/2(2)

x=[-1±√33]/2