Question

4(x+3)²=25(x_2)² solve the following by quadratic equation​

Answer 1

Answer:

4(x + 3)^2 = 25(x - 2)^2

4(x^2 +9 + 6x) = 25( x^2 + 4 - 4x )

4x^2 + 36. + 24x = 25x^2 + 100 - 100x

21x^2 + 64 - 124x = 0

=> 21x^2 - 124x + 64 = 0

This is the quadratic equation:

just solve and u will get the answer.

Formula: x = -b +- √b^2 - 4ac

2a

Answer 2

Step-by-step explanation:

4(X+3)²=25(x-2)²

or,4(x²+6x+9)=25(x²-4x+4)

or,4x²+24x+36=25x²-100x+100

or,0=25x²-4x²-100x-24x+100-36

or,0=21x²-124x+64

or,0=(7x-5)(3x-16)

either,. or,

(7x-5)=0. (3x-16)=0

or, 7x=5. or,3x=16

or,X=5/7. or,X=16/3