Question

4^x– 3.2^x+2 +32 = 0​

Answer 1

Answer:

2 and 3

Step-by-step explanation:

4^x -3.2^x+2 +32=0

or, 2^2x - 3.2^x.2^2 +32 =0

or, a^2 - 3.a.4+32 =0 ; [ 2^x=a ]

or, a^2 -12a + 32 =0

or, a^2 - 4a-8a +32 =0 ; [ middle term ]

or, a ( a-4) -8 (a-4) =0

or, (a-8) (a-4)=0

or, a= 8 and a= 4

if a=8,

or, 2^x= 8

or, 2^x= 2^3

so, x = 3

again, if a=4,

or, 2^x=2^2

so, x= 2