Question

4^x-3×2^x+2+32=0 find the value of x​

Answer 1

4^(x-3) * 2^(x+2) +32 = 0

since 4 = 2^2

so 4^(x-3)= 2^2(x-3)

2^2(x-3) * 2^(x+2) = -32

2^(2x-6+x+2) = -32

2^(3x-4) = negative

this is not possible as any power of a positive number cannot be negative

hence solution does not exist

x is imaginary