4(x + 3) − 7 ≥ x + 3(x + 1)
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Answered by
1
267181
Step-by-step explanation:
62781+83828
=178273
hence proved
Answered by
0
Answer:
We have , 4(x+3)-7≥ x+3(x+1)
Then we have to open the brackets, 4x+12-7 ≥ square of x +x+3x+3
4x+5 ≥ square of x+4x+3
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