Question

4(x-3)-(x-5)=0 linear equation​

Answer 1

$4(x - 3) - (x - 5) = 0$

$4x - 12 - x + 5 = 0$

$3x - 7 = 0$

$3x = 7$

$x = \frac{7}{3}$

Answer 2

Answer:

=> The value of x is $\frac{7}{3} .$

Step-by-step explanation:

Given that:-

$4(x-3)-(x-5)=0$

To find:- The value of the expression,

To solve this expression, we have to use the transposition method:

As we have,

=> $4(x-3)-(x-5)=0$

Distribute the terms, we get

=> $4x-12-x-5=0$

=> $4x - 7 -x = 0$

Combine like terms, we get

=> $3x - 7 = 0$

Add both sides by $7$, we get

=> $3x - 7+7 = 0+7$

=> $3x = 7$

Divide both sides by $3$,

=> $x = \frac{7}{3}$

Hence, the required solution is $\frac{7}{3} .$