Question

4^x ×4^-8 =4^-3 find the x

Answer 1

Answer:

Step-by-step explanation:

4^x x 4^-8 = 4^-3

4^(x+(-8)) = 4^-3

4^(x-8) = 4^-3 (when 4 goes to other side in reciprocating, it gets cancelled)

4^(x-8)/4 = 1^-3

1^(x-8) = 1^-3

x-8 = (-3)

x = (-3) + 8

x = 8 - 3

x = 5