4^x_4^x_1=24. then (2x)^x
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4x−4x−1=24
or 4x(1−4/1)=24
or 4x4/3=24
or 4x=(24×4)/3=32=25
or 2^2x=25 or x=25
or 2x=5 or (2x)^x=(5)^5/2=5^1×5^1×5^1/2=
25√5
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