Math, asked by gokul67, 1 year ago

4^x-4^x-1=24 what is the value of (2x)^x​

Answers

Answered by ihrishi
1

Answer:

 {4}^{x}  -  {4}^{x - 1}  = 24 \\  {4}^{x}  -  {4}^{x}  \times  {4}^{ - 1}  = 24 \\  {4}^{x} (1 -  \frac{1}{4}) = 24 \\  {4}^{x}  \times  \frac{3}{4}  = 24 \\  {4}^{x}  = 24 \times  \frac{4}{3}  \\ {4}^{x}  = 8 \times4 \\  {2}^{2x}  = 32 \\ {2}^{2x}  = {2}^{5}  \\ 2x = 5 \\ x =  \frac{5}{2}  \\ (2x) ^{x}  = (2 \times  \frac{5}{2} )^{ \frac{5}{2} }  = 5^{ \frac{5}{2} } \:

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