Question

(4+x) (5-x)/(2+x) (7-n) =1 Please give a photo​

Answer 1

Answer:

n=

7x2−6x−138

x2−x−20

Step-by-step explanation:

Let's solve for n.

(4+x)(5−x)

2+x

(7−n)=1

Step 1: Multiply both sides by x+2.

nx2−nx−7x2−20n+7x+140=x+2

Step 2: Add 7x^2 to both sides.

nx2−nx−7x2−20n+7x+140+7x2=x+2+7x2

nx2−nx−20n+7x+140=7x2+x+2

Step 3: Add -7x to both sidnx2−nx−20n+7x+140+−7x=7x2+x+2+−7x

nx2−nx−20n+140=7x2−6x+2

Step 4: Add -140 to both sides.

nx2−nx−20n+140+−140=7x2−6x+2+−140

nx2−nx−20n=7x2−6x−138

Step 5: Factor out variable n.

n(x2−x−20)=7x2−6x−138

Step 6: Divide both sides by x^2-x-20.

n(x2−x−20)

x2−x−20

=

7x2−6x−138

x2−x−20es.

Answer 2

(4+x) (5-x). (7-n)=1

________

(2+x)