4/x+5/y=7, 5/x+4/y=13/2,Solve the given pair of equations by the method of elimination
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Solution :
4/x + 5/y = 7 ---( 1 )
5/x + 4/y = 13/2 ---( 2 )
Let 1/x = a , 1/y = b
4a + 5b = 7 ---( 3 )
5a + 4b = 13/2 --( 4 )
[ 5 × ( 3 ) - 4 × ( 4 ) ]
20a + 25b = 35----( 5 )
20a + 16b = 26 ----( 6 )
_____________
•••••••• 9b = 9
=> b = 9/9
=> b = 1
Put b = 1 in equation ( 3 ), we get
4a + 5 × 1 = 7
=> 4a = 7 - 5
=> 4a = 2
=> a = 2/4
=> a = 1/2
Therefore ,
1/x = a = 1/2
=> x = 2 ,
1/y = b = 1
=> y = 1
••••
4/x + 5/y = 7 ---( 1 )
5/x + 4/y = 13/2 ---( 2 )
Let 1/x = a , 1/y = b
4a + 5b = 7 ---( 3 )
5a + 4b = 13/2 --( 4 )
[ 5 × ( 3 ) - 4 × ( 4 ) ]
20a + 25b = 35----( 5 )
20a + 16b = 26 ----( 6 )
_____________
•••••••• 9b = 9
=> b = 9/9
=> b = 1
Put b = 1 in equation ( 3 ), we get
4a + 5 × 1 = 7
=> 4a = 7 - 5
=> 4a = 2
=> a = 2/4
=> a = 1/2
Therefore ,
1/x = a = 1/2
=> x = 2 ,
1/y = b = 1
=> y = 1
••••
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