4^x+6^x=9^x
find the value of X
177uzairr3:
x=0
x=0 is 1 and 1+1 is 2 not 1 sorry your answer is wrong
your are a big donkey
1+1 how the second one came tell me loser
abe kutte teri maa donkey
Answers
Answered by
2
Answer:
x=
ln3−ln2
ln(1+
5
)−ln2
.
Step-by-step explanation:
6
x
+4
x
=9
x
divide by 4
x
to form (
2
3
)
x
4
x
6
x
+1=
4
x
9
x
(
2
3
)
x
+1=(
2
3
)
2x
((
2
3
)
x
)
2
−(
2
3
)
x
−1=0
So (
2
3
)
x
=
2
1±
1−4.1(−1)
=
2
1±,
5
For positive solution
(
2
3
)
x
=
2
1+
5
Applying logarithm
xln(
2
3
)=ln(
2
1+
5
)
ln
b
a
=lna−lnb
x=
ln3−ln2
ln(1+
5
)−ln2
.
Answered by
1
Answer:
x=2
Step-by-step explanation:
4^x+6^x=9^x
10^x=9^x
10^x-9^x=?
1^x÷1=1
x=1
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