4. X and y can do a piece of work in 30 days. They work together for 6 days and then x quits and y finishes the work in 32 more days. In how many days can y do the piece of work alone?
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0
"(X Y)'s 6 day's work = 6∗1/30=15
"remaining work = 1 - 1/5=4/5
"4/5 of work is done by Y in 32 days
"whole work can be done by Y in {32 * 5}/{4} = 40 days
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Answered by
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Let the total unit of work be 480 units. (LCM of 30 and 32)
X and Y together complete the work in 30 days.
(X+Y)do=
30/480
=16 units/day
According to the question,
16×6+Y×32=480
Y×32=384
Y=12
Y does =12 units/day.
Y alone can complete the work =
12/480 = 40 days.
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