Question

4. X can do a piece of work in 25 days and Y can finish it in 20 days. They work together for 5 days and
then Y leaves. In how many days will X finish the remaining work?
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Answer 1

Answer:

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Answer 2

y can do a work in 20 days and x can do the same work in 25 days, they started work together, after 5 days y left the work, in how many days x will finish the remaining work?

In 1- day x and y can do= 1/20+ 1/25 = 9/100.

In 5- days both can do= 9/100 x 5 =45/100.

Number days required by x to finish the remaining work= (55/100)÷(1/20) = 11- days.

========================== Another method x does the work till the end and y does the work for 5- days only.

If the total work if finished in a- days, then

So a/20 + 5/25= 1

5a+ 20= 100

a= 80/5= 16.

So complete work is done in 16- days.

A alone does after y- left= 16–5= 11- days !!!