Math, asked by Smitanautiyal2006, 11 months ago

4 x cube minus 8 x square + 8 x + 1 divided by x + 3

Answers

Answered by Anonymous

1

Step-by-step explanation:

4x^3-8x^2+8x+1÷x+3

substitute x=-3

4(-3)^3-8(-3)^2+8(-3)+1

4(-27)-8(9)-24+1

-108-72-24+1

-203

Answered by leelamewara125

0

Answer:4x^2-20x+68

remainder=-203

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