4 x cube minus 8 x square + 8 x + 1 divided by x + 3
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Answered by
1
Step-by-step explanation:
4x^3-8x^2+8x+1÷x+3
substitute x=-3
4(-3)^3-8(-3)^2+8(-3)+1
4(-27)-8(9)-24+1
-108-72-24+1
-203
Answered by
0
Answer:4x^2-20x+68
remainder=-203
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