4 x minus 3 y ka whole cube plus 4 x + 3 y ka whole cube solve this question using identity
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Answer:
(4x-3y)³.
It is in the form of (a-b)³=a³-b³-3ab(a-b).
Where a=4x & b=3y.
(4x-3y)³=(4x)³-(3y)³-3(4x)(3y)(4x-3y).
=64x³-27y³-144x²y+108xy². (Because -×-=+).
(4x+3y)³.
It is in the form of (a+b)³=a³+b³+3ab(a+b).
Where a=4x & b=3y.
(4x+3y)³=(4x)³+(3y)³+3(4x)(3y)(4x+3y).
=64x³+27y³+144x²y+108xy².
I think this is your answer.
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