Question

4 x square - 5 x minus 3 is equals to zero solve by using formula your answer correct to 2 decimal place

Answer 1

Question :-

→ 4x² - 5x - 3=0 solve by using the quadratic formula .

Answer :-

$\implies \boxed{\sf{ x = 1.69\: \: and \: 0.44}} \:$

Explanation :-

We have

→ 4x² - 5x - 3 = 0

And ,we know that if we have a quadratic

ax² + bx + c = 0 .....eq.(1)

,then by using quadratic formula i.e,

$\implies \boxed{\sf{x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac} }{2a} }}$

Compare the given quadratic equation with eq.(1)

We get

→ a = 4 , b = -5 and c = -3

Hence , using the given formula

$\implies \sf{ x = \frac{ - ( - 5) \pm \sqrt{ {( - 5)}^{2} - 4 \times 4 \times ( - 3) } }{2 \times 4} } \\ \\ \implies \sf{x = \frac{5 \pm \sqrt{25 + 48} }{8} } \\ \\ \implies \sf{x = \frac{5 \pm \sqrt{73} } {8} } \\ \because \boxed{ \sqrt{73} = 8.54} \\ \\ (1) \bf \: if \: + \\ \\ \to \sf{} x = \frac{5 + 8.54}{8} = \frac{13.54}{8} = 1.69\\ \\ (2) \bf if \: - \: \\ \\ \to \sf{}x = \frac{5 - 8.54}{8} = \frac{ - 3.54}{8} =0.44 \\ \therefore \\ \implies \boxed{\sf{ x = \: 1.69 \: and \: 0.44}}$

Answer 2

$\tt{\huge{\orange {Hello!!! }}} S.D$

QUESTION :

4 x square - 5 x minus 3 is equals to zero solve by using formula your answer correct to 2 decimal place.

SOLUTION :

f(x) => 4 x^2 - 5 x - 3

From the equation,

B = -5

A = 4

C = -3

=> - B = 5

=> D = √ [ b^2 - 4 ac ] = √ [ 25 - 4 × 4 × - 3 ] = √ [ 25 + 48 ] = √ 73.

2A = 8

=> Roots :

{ 25 - √ 73 } / 8 and { 25 + √ 73 } / 8

√ 73 to 2 digits decimal place = 8.54

=> Root 1 = { 25 + 8.54 } / 8 = 1.69........(A1)

=> Root 1 = { 25 - 8.54 } / 8 = 0.44........(A2)