Question

4 x square-5root 2x - 3 find the roots and verify the relationship between zeroes and coefficients​

Answer 1

Answer:

P(X) = 4X²+5✓2X-3

=> 4X²+6✓2X-✓2X-3

=> 2✓2X(✓2X+3) -1(✓2X+3)

=> (✓2X+3) (2✓2X-1) = 0

=> (✓2X+3) = 0 OR (2✓2X-1) = 0

=> X = -3/✓2 OR X = 1/2✓2

-3/✓2 and 1/2✓2 are the two zeros of the given polynomial.

Let Alpha = -3/✓2 and beta = 1/2✓2

Relationship between the zeros and Coefficient.

Sum of Zeros= (Alpha + Beta) = -3/✓2 + 1/2✓2 = -3×2✓2 + ✓2 = -6✓2+✓2/4 = -5✓2/4 = -( Coefficient of X/Coefficient of X².

And,

Product of zeros = (-3/✓2 × 1/2✓2) = -3/4 = Constant term/Coefficient of X².

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Answer 2

Answer:

Find the attachment

Step-by-step explanation:

You cna add alpha and beta and multiply alpha to beta to get-b#÷a and c÷a respectively

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