4(x+y)²-16 factorise it
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Answer:
Step-by-step explanation:
I factored x6−64 as a difference of squares, and then tried it as a difference of cubes, but was left with (x2−4)(x4+4x2+16) is there a general method for factoring x4+4x2+16?It factors into two irreducible quadratic trinomials, which is where I think the problem is stemming from.
nickkaushiknick:
just consider x^2 as a and then you'll ger
get a^2 + 4a + 16
factorise it and put back value of a as x^2 and solve it further
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Answer:
[2x + 2y + 4] [2x + 2y - 4]
Step-by-step explanation:
4(x + y)² - 16
[2(x + y)]² - 4²
Considering 2(x + y) as a and 4 as b, you can observe that given expression is of the form a² - b², which is equals to (a + b) ( a - b )
putting a = 2( x + y) and b = 4
∴[2(x + y) + 4] [2(x + y) - 4]
[2x + 2y + 4] [2x + 2y - 4]
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