Question

4 x + Y - 3 Z ^2
bhai jaldi ans​

Answer 1

Answer: ↓

(4x−2y−3z)^2

We know that (x+y+z)^2 = x^2+y^2+z^2+2xy+2yz+2xz

Here x=4x, y=-2y and z=-3z we get

(4x−2y−3z)^2=(4x)  ^2+(−2y)^2+(−3z)  ^2+2(4x)(−2y)+2(−2y)(−3z)+2(4x)(−3z)

=16x^2+4y^2+9z^2−16xy+12xy−24xz