Math, asked by chatterjeesananda6, 9 months ago

4(x-y-z) ²-(y-z+x)²​

Answers

Answered by RITWIKADUTTA
1

Step-by-step explanation:

4(x-y-z)^2 - (y-z+x)^2

=4x^2-4y^2-4z^2+y-z+x

=4x^2+x-4y^2+y-4z^2-z

=5x^2+5y^2+5z^2

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Answered by sayan3463
0

Step-by-step explanation:

4(x-y-z)2 - (y-z+x) 2

= 4(x - y - z) 2 - (x + y - z)2

= 4{(x-y-z)+(x+y-z)}{(x-y-z) - (x+y-z) }

= 4{x-y-z+x+y-z}{x-y-z-x-y+z}

= 4{2x - 2z}{-2y}

= 8y - (2x - 2z)

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