Question

4 x2 +4root of 3x +3=0​

Answer 1

$4x {}^{2} + 4 \sqrt{3} x + 3 = 0 \\ 4x {}^{2} + 2 \sqrt{3} x + 2 \sqrt{3} x + 3 = 0 \\ 2x(2x + \sqrt{3} ) + \sqrt{3} (2x + \sqrt{3} ) = 0 \\ (2x + \sqrt{3} )(2x + \sqrt{3} ) = 0 \\ 2x + \sqrt{3} = 0 \\ 2x = - \sqrt{3} \\ x = - \frac{ \sqrt{3} }{2} \\ \\ or\\ \\ 2x + \sqrt{3} = 0 \\ 2x = - \sqrt{3} \\ x = - \frac{ \sqrt{3} }{2}$

I hope that helps you dear.....

Answer 2

8+√4*3x+3=0=8+2+3x+3=0=13+3x=0=3x=-13=x=-13/3