Question

4) x2 - 4x +16= 0
(3) 25
The equation whose roots are twice th
roots of the equation x2 - 2x + 4 = 0 is
(1) x2 - 2x + 4 = 0
(2) x2 - 2x +16=0
3) x2 - 4x + 8 = 0​

Answer 1

Answer:

Given quadratic equation is x2−2x+4=0

Let α and β be the roots of the equations.

Thus α+β=2,αβ=4

∴2α+2β=4,4αβ=16

Therefore, the equation is x2−4x+16=0.

Answer 2

Now compare the both equations and their solution

2nd equation solution has double than 1st equation....

I hope that this helps you ....

All the best