4-x2-y2-2xy factorise
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1
Answer:
Step-by-step explanation:
4-x^2-y^2-2xy
2^2-x^2-y^2-2xy
Using law a^2-b^2=(a+b)(a-b)
(2+x+y)(2-x-y)
Answered by
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4 - x^2 - y^2 - 2xy
= 4 - (x^2 + y^2 + 2xy)
= 2^2 - (x + y)^2
= (2 - (x + y))(2 + (x + y))
= (2 - x - y)(2 + x + y)
= 4 - (x^2 + y^2 + 2xy)
= 2^2 - (x + y)^2
= (2 - (x + y))(2 + (x + y))
= (2 - x - y)(2 + x + y)
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