Math, asked by lordofficial44, 6 hours ago

4-x2-y2-2xy factorise

Answers

Answered by utkarshbhradwaj
1

Answer:

Step-by-step explanation:

4-x^2-y^2-2xy

2^2-x^2-y^2-2xy

Using law a^2-b^2=(a+b)(a-b)

(2+x+y)(2-x-y)

Answered by 2dots
1
4 - x^2 - y^2 - 2xy
= 4 - (x^2 + y^2 + 2xy)
= 2^2 - (x + y)^2
= (2 - (x + y))(2 + (x + y))
= (2 - x - y)(2 + x + y)
Similar questions