Question

4. XYZ is a right-angled triangle with ZX = 90° , XY = 9 cm, and YZ=12 cm. OX is perpendicular to YZ.
Find OX

pl solve using pythogoras theorem.. ​

pl answer it's urgent

Answer 1

$\huge❥{\underline{\mathtt{\red{A}\pink{N}\green{S}\blue{W}\purple{E}\orange{R}}}}$

XYZ is a right angled triangle with X=90°, XY=9cm, and YZ=12cm

(YZ)²  = (XY)² + (XZ)²

=> 12² = 9² + (XZ)²

=> 144 = 81 +  (XZ)²

=> 63 =  (XZ)²

=> XZ = √63

=> XZ = 3√7  cm

Area of Triangle  ΔXYZ  = (1/2)XY * XZ   = (1/2)YZ*OX

=> XY *XZ = YZ * OX

=> 9 * 3√7 = 12 * OX

=> 9√7 / 4 = OX

OX = 9√7 / 4  cm