Question

4(х+y)^2 - 40( x+y)​

Answer 1

Answer:

$4( {x + y})^{2} - 40(x + y) \\ \\ = 4( {x}^{2} + 2xy + {y}^{2} ) - 40 x- 40y \\ \\ = {4x}^{2} + 8xy + {4y}^{2} - 40x - 40y \\ \\ = {4x}^{2} + {4y}^{2} + 8xy - 40x - 40y \\ \\ = 4( {x}^{2} + {y}^{2} + 2xy - 10x - 10y)$

hope it helps uH ✔

Answer 2

Answer:

loolllkgfdvbgssfhbgh