Question

( 4 y + 3x) dy +(y-2x) dx=0​

Answer 1

Answer:

Assuming you meant (4y + 3x)dy +(y - 2x)dx = 0, we get:

(4y + 3x)dy = -(y - 2x)dx => dy/dx = -(y - 2x)/(4y +3x).

Step-by-step explanation:

Answer 2

Answer:

y= x/2 ln15x(xy/2x-y)⁴ - 2C