Question

4 y cube + 8 y square + 3 Y - 5 divide 4 Y 2​

Answer 1

Answer:

Given : f(x) = y^3 - 8

Given : g(x) = y - 2

y - 2)  y^3  + 0y^2 + 0y -  8 (y^2 + 2y + 4

         y^3  -  2y^2

        -------------------------------

                    2y^2        -  8

                   2y^2  -  4y

         --------------------------------

                                 4y   -  8

                                 4y   -  8

          ----------------------------------

                                         0.

Therefore, Quotient = y^2 + 2y + 4 and remainder = 0.

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