Question

4 y square + 3 Y + 5 barabar 0 Ka Haal Kitna hoga

Answer 1

4y² + 3y + 5 = 0

The roots will be imaginary.

y = {-b ± Root of (b² - 4ac)} / 2a.

Here, b = 3; a = 4; c=5

Since the roots are imaginary, therefore you would not get any simplified answer. You may put the values to get the required answer. If you would like me to do that, please comment.