Math, asked by darkff0089, 3 months ago

4 years ago Father was 5 times as old as his son was. After 4 years Father will
be 3 times as old as his son will be. Then the present ages of their are​

Answers

Answered by devsingh83
0

Answer:

LET THE SON’SAGE BE X

THEN FATHR’S AGE WOULD BE= 4X

AFTER 5 YEARS SONS AGE WILL BE 9X+5) AND FATHER’S AGE WOULD BE (4X+5)

IT IS GIVEN THAT THE FATHER WOULD BE 3 TIMES OF THE AGE OF HIS SON

THEREFORE,(4X+5)= 3(X+5)

SIMPLIFYING WE HAVE 4X-3X= 15–5= 10

HENCE SON’S AGE NOW IS 10YRS FATHERE’S AGE IS 4x X=4*10=40

AFTER 5 YRS SON

S AGE WILL BE 10+5=15 YRS

FATHER’S AGE= 40+5=45 WHICH IS 3 TIMES THE AGE OF HIS SON

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