Question

4 years ago father was six times as old as his son ten years later the father will be twice as old as his son determine the present age of father and son
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Answer 1

Answer:

Let the present age of son be x. ∴Son's present age = x = 12.5years = 12 years and 5 months. ∴Father's present age = 10 years after - 10 years before = 5/2[x+6] - 10 = 36.2 years = 36 years and 2 months.

Step-by-step explanation:

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